AIEEE sample practice questions in Permutation in Numbers - Divisibility : AIEEE Math : Fermat Education - AIEEE Classes

AIEEE.BE - AIEEE Classes, Correspondence Course, Practice Tests  
AIEEE Classes
AIEEE Study Material
AIEEE Questionbank
AIEEE Practice Tests
AIEEE Forum
Top Engineering Colleges
 
AIEEE Crash Course
AIEEE Crash Course 1 month intensive classes for AIEEE @ Chennai starts in March 2011. At Anna Nagar, Mylapore and Tambaram.
AIEEE classroom courses
 
Other Links
AIEEE Practice Questions
AIEEE Math Forum
AIEEE Physics Forum
AIEEE Chemistry Forum
AIEEE Prep Blog
 
Other Courses
CAT Classes & Courses
TANCET Correspondence Course
PGSEM Test Correspondence
GMAT Classes
GRE Classes
SAT Classes
 
Contact Us
+91 44 4500 8484
+91 44 3912 4040
93825 48484
info@aieee.be
Postal Address
You are here: AIEEE Classes » AIEEE Prep Questions » Math » Permutation Combination » Question 4

Permutation Combination : Numbers : Divisibility

Question 4
Using the digits 2, 3, 4 how many 3-digit numbers can be formed that are divisible by 3? The digits can be repeated.
  1. 9
  2. 8
  3. 7
  4. 10
Correct Answer is 9. Choice (A).

Explanatory Answer

222, 333 and 444 are divisible by 3.

All six arrangements of the digits 2, 3, 4 (234, 243, 324, 342, 423, 432) are also divisible by 3.

There are 9 possible solutions.

Answer is choice A.


AIEEE Math Problems, Practice Questions and Answers : Listed Topicwise

Sets, Relations & Functions
  
Permutation Combination
  
Sequences & Series
Limits, Continuity & Differentiability
  
Statistics & Probability
  
Trigonometry
Mathematical Reasoning
  
 
  
 




Add to del.icio.us Add to del.icio.us Stumble It Stumble It digg this digg this
Top NITs, Engineering Colleges in India | AIEEE FAQ | Faculty List | AIEEE Mailing List
Disclaimer | Privacy Policy | Terms of Use | © 2010 Fermat Education. All rights reserved.
The CBSE board or AIEEE is not affiliated with Fermat Education or AIEEE.BE and does not endorse this web site.